25n+15-14n^2=0

Solution for 25n+15-14n^2=0 equation:

25n+15-14n^2=0

a = -14; b = 25; c = +15;
Δ = b2-4ac
Δ = 252-4·(-14)·15
Δ = 1465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1465}}{2*-14}=\frac{-25-\sqrt{1465}}{-28}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1465}}{2*-14}=\frac{-25+\sqrt{1465}}{-28}
$